在做隧道ANSYS简单开挖模拟时,出现了一些问题,望各位前辈给多多指教! zdYjF|
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隧道洞泾假定为1.0m(实际上不可能这么小,仅仅是数值实验),隧洞轴线左右及下部各取10m为边界,施加法向约束。 vt8By@]:
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通过APDL命令,改变隧道的轴线埋深,采取全断面一次性开挖,整个荷载步分为两步:第一步计算初始应力场,第二步是杀死 $]d^-{|
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开挖体单元,计算开挖后引起的地表沉降(位移场,第二步减去第一步),计算结果发现: L_T5nD^D
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隧道的轴线埋深越浅,计算得到的地表沉降越小,这与工程实际不符,请问原因何在? ]/Pn
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以下是我的计算命令流,希望得到高手的帮助啊! ,prf;|e?
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Fini 2ESo2
/clear 3S{/>1Y
/title,TUNNEL ANALYSIS .]^?<bG
/prep7 wT@og|M
ET,1,PLANE2 Dtk=[;"k2a
keyopt,1,3,2 _XBd3JN@
UNYqft4
*SET,R,0.7 5+vaE
2v
*SET,H,10.0 AH^/V}9H
*SET,X1,-2*R A"]YM'.
*SET,Y1,-2*R p{_" bB
*SET,W1,4*R Y4-t7UlS;
*SET,H1,4*R Ac@VGT:9
3BI1fXT4=j
*SET,X2,-10.0 7! Nsm
*SET,Y2,H-20.0 OXA7w.^
*SET,W2,20.0 %EH)&k
*SET,H2,20.0 &
21%zPm
CYL4,0,0,0,45,R,405,0 h`q1
BLC4,X1,Y1,W1,H1 ]M=&+c>H~
BLC4,X2,Y2,W2,H2 *@5 @,=d
AOVL,1,2,3 f|5co>Hk
NUMCMP,ALL 4Z*/WsCv
NUMMRG,ALL,,,,LOW :;}P*T*PU
LANG,11,8,90,, i5Ggf"![
LANG,11,7,90,, ye&;(30Oq
LANG,10,7,90,, T)/eeZ$
LANG,10,6,90,, fhiM U8(&
LANG, 9,6,90,, M3\AY30L
LANG, 9,5,90,, ?s01@f#
LANG,12,5,90,, Cdn J&N{
LANG,12,8,90,, [y(MCf19
L,1,7 [0!( xp^
L,2,8 /uflpV|
L,3,5 9[4xFE?|
L,4,6 e'~3oqSvR
NUMCMP,ALL WWY6ha
NUMMRG,ALL,,,,LOW 7Q 3 k7
FLST,3,4,4,ORDE,2 ?<!|
FITEM,3,29 )lkjqFQ(
FITEM,3,-32 kiEa<-]
ASBL,2,P51X 7CysfBF0g
FLST,3,8,4,ORDE,8 i!Ba]n
FITEM,3,14 6nn*]|7
FITEM,3,16 t@(HF-4~=
FITEM,3,18 4#D,?eA7
FITEM,3,20 }BEB1Q}L
FITEM,3,22 6ujWNf
FITEM,3,24 \fOEqe*5SM
FITEM,3,26 Rq -ZL{LR7
FITEM,3,28 97Vtn4N3
ASBL, 3,P51X c<~H(k'+c
NUMCMP,ALL ).O)p9
NUMMRG,ALL,,,,LOW *. t^MP
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!初始参数 ?ub35NLa
MP,EX,1,3.0E6 @7}W=HB
MP,PRXY,1,0.33 4g/dP^
MP,DENS,1,1900.0 3]hWfj1m2
TB,DP,1 kJU2C=m@e2
TBDATA,1,2.4E4,13.6,0 X}]-*T|a
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MP,EX,2,3.0E6 +@UV?"d
MP,PRXY,2,0.33 ?dTD\)%A
MP,DENS,2,1900.1 rv;3~'V
TB,DP,2 BtZ yn7a
TBDATA,1,2.4E4,13.6,0 'u658Tj
crCJrN=
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!剖分单元 z?zL9 7H
type,1 4-w{BZuS
MAT,1 lZ0 =;I
lsel,S,line,,1,8,1 `cO:<^%
lsel,A,line,,15,27,4 iU-j"&L5
Lesize,ALL,,,4,,,,,0
kAx4fE[c
lsel,S,line,,29,32,1 bt *k.=p
Lesize,ALL,,,3,,,,,0 Kw}'W
8` c
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lsel,S,line,,9,13,2 }]TxlSp!;
lsel,A,line,,18,20,2 *Ex|9FCt$
lsel,A,line,,21 L];b<*d
lsel,A,line,,26,28,2 =a!=2VN9y
Lesize,ALL,,,10,,,,,0 g0H[*"hj
lsel,S,line,,10 8L XHk l
lsel,A,line,,22 $>gFf}#C
lsel,A,line,,24,25,1 $'TM0Yu,
Lesize,ALL,,,20-H-2*R,,,,,0 w!CNRtM:~
lsel,S,line,,12,14,2 mOSv9w#,
lsel,A,line,,16,17,1 N!3 2 wJ
Lesize,ALL,,,H-2*R,,,,,0 !k%#R4*>
asel,s,area,,2,13,1 [lAp62i5
amesh,all K,]=6Rj
Ru XC(qcq
type,1 0V]s:S
MAT,2 -di o5a
asel,s,area,,1 !wNO8;(
amesh,all 67TwPvh
nummrg,all,,,,low D$N/FJ8|G
numcmp,all ,Q,^3*HX9}
$(9U @N9E
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!计算初始应力场 v<;Md-<
/solu >7r!~+B"9'
antype,static #g=XUZ/"
deltim,0.1,0.05,0.2 l~.-e^p?
autots,on !使用自动时间步 %SI'BJ
pred,on !打开时间步长预测器 bcR_E5x$
lnsrch,on !打开线性搜索 "3hMq1NQ`g
nlgeom,on !打开大位移效果 ] - .aL
nropt,full !设定牛顿-拉普森选项 '|4!5)/K
cnvtol,f,,0.02,0 *H122njH+T
Nsel,s,loc,x,-10 SaCh
7 ^
Nsel,a,loc,x,10 1}37Q&2
D,all,,,,,,UX,,,,, R3!t$5HG
Nsel,s,loc,y,H-20 C?Ucu]cW
D,all,,,,,,Uy,,,,, 2oU_2P
time,1 G`zm@QL
acel,,10 ccnK#fn v
nsel,all {[(h[MW#
esel,all xpI wrJO
allsel,all ,47qw0=C
solve
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!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!开挖 dd["dBIZ '
time,2 Wf<LR3
esel,s,type,,2 jIF
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ekill,all |' .
nsel,all w:l"\Tm
esel,all 6Iw\c
allsel,all e*!kZAf
solve x :7IIvP
fini <1pEwI~
aP`P)3O6)1
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!地表沉降 +O5hH8<&b
!/POST1 Q &t<Y^B
!LCDEF,1,1,, ^J d
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!LCDEF,2,2,, 2[CdZ(k]5
!LCASE,2, PzGWff!*n
!LCOPER,SUB,1, ,2, Gc!x|V;T
!Nsel,s,loc,Y,H }-fl$j?9E
!PLVECT,U, , , ,VECT,ELEM,ON,0 2-b6gc7
!PLNSOL, U,Y, 0,1.0 X?$_Sd"G+5
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